VELOCITY
T
0 1 2 3 4 5 6 7 8 |
X
0 -2 -4 -2.5 -1.5 -1.5 -2.5 -2 -1.5 |
V
0 -2 -2 1.5 1 0 -1 0.5 0.5 |
Using the graphs above..
Q1) How much distance is travelled 0s-5s?
A) 4m (1st segment)+3(second segment) --> 5.5m
Q2) What is the displacement from 0s-5s?
A) (delta)X=X-Xo ----(deltaX=final position-initial position)
deltaX=-1.5 - 0 --> or -1.5m
Q3) What is the speed from 0s-5s?
A) distance/time(s)
6.5m/5s
1.3m/s
Q4) What is the velocity from 0s-5s?
A) deltaX /time(s)
-1.5m/5s
0.3m/s
Q1) How much distance is travelled 0s-5s?
A) 4m (1st segment)+3(second segment) --> 5.5m
Q2) What is the displacement from 0s-5s?
A) (delta)X=X-Xo ----(deltaX=final position-initial position)
deltaX=-1.5 - 0 --> or -1.5m
Q3) What is the speed from 0s-5s?
A) distance/time(s)
6.5m/5s
1.3m/s
Q4) What is the velocity from 0s-5s?
A) deltaX /time(s)
-1.5m/5s
0.3m/s
How I got the the...
Points for the position-time or xt graph: I multiplied the time value (in s) by the velocity value (m/s). For example, for the first second, I multiplied 1* -2 --> -2m. Same goes for the 2nd second: 2s* -2m/s =-4. I just added on the m values. For seconds 2-->3, I multiplied 1s*1.5m/s=1.5 and then 1s*-2=-2. I added 1.5 to -4 which gave me the answer of -2.5m. I applied the same concept for the rest of the values. Also, for seconds 4 -->5, since there was no motion, the position remained at the constant position of -1.5.
Work:
0-2s: 2s*-2m/s=-4 ---> -4
2-3s: 1s*1.5m/s=1.5 ---> -2.5
3-4s: 1s*1m/s=1 ---> -1.5
4-5s: 1s*0m/s=0 ---> -1.5
5-6s: 1s*-1m/s=-1 ---> -2.5
6-8s: 2s*0.5m/s=1 ---> -1.5
Position-time Graph: I plotted the m values (shown above) corresponding with their (t) values on to a graph.
Motion Map:
The first arrow shows -2 and so does the second arrow, both totaling -4m. In the third second, it travels 1.5m --in a positive direction. The 4th second, a distance of 1m is travelled. The two dots stacked up on top of each other show no movement for one second. Then, at the 6th dot/second, the object travels in a negative direction again --negative slope on graph for 1m. The next two dots or seconds show 6-8s. The distance traveled each second is 0.5m at a positive slope.
Work:
0-2s: 2s*-2m/s=-4 ---> -4
2-3s: 1s*1.5m/s=1.5 ---> -2.5
3-4s: 1s*1m/s=1 ---> -1.5
4-5s: 1s*0m/s=0 ---> -1.5
5-6s: 1s*-1m/s=-1 ---> -2.5
6-8s: 2s*0.5m/s=1 ---> -1.5
Position-time Graph: I plotted the m values (shown above) corresponding with their (t) values on to a graph.
Motion Map:
The first arrow shows -2 and so does the second arrow, both totaling -4m. In the third second, it travels 1.5m --in a positive direction. The 4th second, a distance of 1m is travelled. The two dots stacked up on top of each other show no movement for one second. Then, at the 6th dot/second, the object travels in a negative direction again --negative slope on graph for 1m. The next two dots or seconds show 6-8s. The distance traveled each second is 0.5m at a positive slope.